[xsl] Filling gaps in a list of values

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Subject: Filling gaps in a list of values
From: "Ben Hesketh" <jbgh2@xxxxxxxxxxx>
Date: Tue, 22 Jan 2002 12:58:47 +0000

Hi,

I'm trying to sort a set of nodes in descending order and output them with any gaps filled in.

ie

<node order="1" name="fred"/>
<node order="4" name="bob"/>

will produce

order 4: bob
order 3: no name
order 2: no name
order 1: fred

I've tried using <xsl:for-each> but I can't seem to get hold of the next node to be processed to check it! I've also tried using <xsl:apply-templates select="node[@order]"> but the template is called once for every node.

Cheers in advance,

BEN


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Current Thread
Filling gaps in a list of values Ben Hesketh - Tue, 22 Jan 2002 07:57:17 -0500 (EST) <= Jeni Tennison - Tue, 22 Jan 2002 08:35:04 -0500 (EST) Andrew Welch - Tue, 22 Jan 2002 09:07:36 -0500 (EST) Jeni Tennison - Tue, 22 Jan 2002 09:46:19 -0500 (EST) <Possible follow-ups> Ben Hesketh - Tue, 22 Jan 2002 09:20:54 -0500 (EST)

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