Subject: RE: How to add a top level element to the result ?
From: "Chris Bayes" <chris@xxxxxxxxxxx>
Date: Thu, 20 Dec 2001 10:05:47 -0000
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> Interesting.....It worked.
Why? That is how xslt works.
> If I change the expression for match to /A/B//C instead of /
> ie,similar to the match expression in the next rule then it
> wont work. Why is it so?
But it will. Try this. But it won't give you the output you want.
<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/A/B//C">
<Message>
<xsl:element name="{@attr1}">
<xsl:apply-templates />
<xsl:value-of select="@attr2"/>
</xsl:element>
</Message>
</xsl:template>
<xsl:template match="T"/>
</xsl:stylesheet>
Ciao Chris
XML/XSL Portal
http://www.bayes.co.uk/xml
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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