RE: [xsl] how to rearrange nodes based on a dependency graph

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Subject: RE: how to rearrange nodes based on a dependency graph?
From: "Chris Bayes" <chris@xxxxxxxxxxx>
Date: Thu, 20 Dec 2001 21:26:05 -0000

What about
<xsl:for-each select='*[not(@requires)]'>
	<xsl:call-template name='copy-stuff'/>
</xsl:for-each>

Ciao Chris

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Current Thread
how to rearrange nodes based on a dependency graph? Gunther Schadow - Thu, 20 Dec 2001 14:19:44 -0500 (EST) Chris Bayes - Thu, 20 Dec 2001 16:22:39 -0500 (EST) <= Chris Bayes - Thu, 20 Dec 2001 16:36:23 -0500 (EST) Gunther Schadow - Thu, 20 Dec 2001 17:00:10 -0500 (EST) Chris Bayes - Thu, 20 Dec 2001 17:24:59 -0500 (EST) Gunther Schadow - Thu, 20 Dec 2001 17:52:01 -0500 (EST)

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