Re: [xsl] Reformatting character strings

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Subject: Re: Reformatting character strings
From: Jörg Heinicke <joerg.heinicke@xxxxxx>
Date: Fri, 16 Nov 2001 19:23:38 +0100

There are much solutions in FAQ and in the list archives. Use substring().

Joerg

Burisch, Curtis wrote:

Hi,

As ususal, I'm sorry if this is in the faq but could someone give me a
pointer on how I can reformat a date (it's in an attribute) from DD/MM/YYYY
format to MM/DD/YY format?

Thanks,
Curtis.

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Current Thread
Reformatting character strings Burisch, Curtis - Fri, 16 Nov 2001 10:33:23 -0500 (EST) cutlass - Fri, 16 Nov 2001 10:48:12 -0500 (EST) Jörg Heinicke - Fri, 16 Nov 2001 11:00:49 -0500 (EST) <= Michael Kay - Fri, 16 Nov 2001 11:30:41 -0500 (EST) <Possible follow-ups> Burisch, Curtis - Fri, 16 Nov 2001 10:53:51 -0500 (EST)

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