Re: FW: [xsl] xpath expression needed

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Subject: Re: FW: xpath expression needed
From: Wendell Piez <wapiez@xxxxxxxxxxxxxxxx>
Date: Tue, 02 Oct 2001 16:24:59 -0400

At 03:25 PM 10/2/01, you wrote:

I want to match all nodes whose following-sibling::level1 has the same value
for @type.  So in this case, only the first 'level1' node would be matched.
How about:

level1[@type = following-sibling::level1/@type]

Would that work?

Yes, except for the small but very important detail that this will give you every level1 that have *any* following-sibling::level1 with a matching @type.

To check just the directly following sibling level1, amend to:

level1[@type = following-sibling::level1[1]/@type]

The rule for node-set equality is in the XPath spec, 3.4. That's what you have inside the predicate (comparing the node-set consisting of @type to the node-set consisting of following-sibling::level1/@type).

Cheers,
Wendell


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Wendell Piez                            mailto:wapiez@xxxxxxxxxxxxxxxx
Mulberry Technologies, Inc.                http://www.mulberrytech.com
17 West Jefferson Street                    Direct Phone: 301/315-9635
Suite 207                                          Phone: 301/315-9631
Rockville, MD  20850                                 Fax: 301/315-8285
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Current Thread
FW: xpath expression needed William Bagby - Tue, 2 Oct 2001 15:44:24 -0400 (EDT) Wendell Piez - Tue, 2 Oct 2001 16:29:32 -0400 (EDT) <= Manu KY - Sat, 6 Oct 2001 12:03:49 -0400 (EDT)

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