Hello.

Oleg Tkachenko wrote:
> Hello there !
> 
> Is there an efficient way to detect by XPath expression (not by a 
pattern) that 
> current node is an attribute node ?
> I know solution like count(../@* | .)=count(../*), but I believe it's 
too 
> unefficient for this simple task.

What about this:

  not(self::* or self::text())

You should add other self::whatever tests (for comments, etc.)
if other node types are also under consideration.

-- 
Alexander E. Gutman

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