[xsl] count all the following nodes of a perticular parent

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Subject: count all the following nodes of a perticular parent
From: Jayaranga Subasinghe <jayarangas@xxxxxxxxxxxxx>
Date: Thu, 28 Jun 2001 15:51:30 +0600

hello,
i want to count all the following nodes from the current node of the same
parent
can anybody give me a way to do this?
thank you

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list

Current Thread
count all the following nodes of a perticular parent Jayaranga Subasinghe - Thu, 28 Jun 2001 06:00:29 -0400 (EDT) <= Jarno Elovirta - Thu, 28 Jun 2001 06:14:48 -0400 (EDT) Michael Kay - Thu, 28 Jun 2001 08:24:31 -0400 (EDT) Wendell Piez - Thu, 28 Jun 2001 15:31:34 -0400 (EDT) <Possible follow-ups> Ben Robb - Thu, 28 Jun 2001 06:12:57 -0400 (EDT)

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Re: Avoiding selection of UNR, Wendell Piez	Thread	RE: count all the following n, Jarno Elovirta
Re: It's going to work, even , David Carlisle	Date	RE: It's going to work, even , Ben Robb
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