Subject: RE: xsl:copy-of
From: "Michael Kay" <mhkay@xxxxxxxxxxxx>
Date: Mon, 21 May 2001 11:33:26 +0100
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> This does the job fine. Now I want to make my XSLT more
> generic so I don't
> have to specifically say that the "<BODY>" is a CDATA
> section. Basically I
> want an exact copy of the original document whatever the
> original document
> may be.
If you're saying, you want CDATA sections in the input to result in CDATA
sections in the output, you can't: the XML parser throws away the
information as to whether the input was CDATA before the XSLT transformer
gets to see it.
This is because in the XPath data model
<BODY><![CDATA[SomeData]]></BODY>
and
<BODY>SomeData</BODY>
are defined to be precisely equivalent: they are simply different ways of
writing the same thing.
Mike Kay
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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