11=1+2+3+5, so that's what I would have expected.  If you'd used count()
instead of sum() I would have expected 4.

PC2

-----Original Message-----
From: John Wang [mailto:jwang@xxxxxxxxxxx]
Sent: May 9, 2001 14:46
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: RE:  Boolean XPath Expression and sum


Here is my XML

<?xml version="1.0"?>
<?xml-stylesheet type="text/xsl" href="notAvailable.xsl"?>
<abuncha>
	<thing>1</thing>
	<thing>2</thing>
	<thing>N/A</thing>
	<thing>3</thing>
	<thing>5</thing>
	<thing>N/A</thing>
</abuncha>

Here is my XSL

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
	<xsl:output method="xml"/>
	<xsl:template match="/">
		<abuncha>
			<xsl:apply-templates/>
			<sum>
				<xsl:value-of
select="sum(//thing[.!=&apos;N/A&apos;])"/>
			</sum>
		</abuncha>
	</xsl:template>
	<xsl:template match="thing[.!=&apos;N/A&apos;]">
		<xsl:copy-of select="."/>
	</xsl:template>
	<xsl:template match="thing[.=&apos;N/A&apos;]">
	</xsl:template>
</xsl:stylesheet>

Here is what I expected:

<?xml version="1.0"?>
<abuncha>
	<thing>1</thing>
	<thing>2</thing>
	<thing>3</thing>
	<thing>5</thing>
	<sum>4</sum>
</abuncha>

Here is what I actually got:

<?xml version="1.0"?>
<abuncha>
	<thing>1</thing>
	<thing>2</thing>
	<thing>3</thing>
	<thing>5</thing>
	<sum>11</sum>
</abuncha>

my question is: Where does the 11 come from?

Thanks in advance.

-John

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