Hi Peter,

In case the value was not a list of entity names, but of type IDREFS,
then the id() function will return a nodeset of nodes that have one of
the id-s in the list as the value of their ID attribute.

Then you could iterate on these ID values -- fortunately, only the
first node having a particular @ID value will be returned (as stated in
Mike Kay's book).

Therefore, the XPath expression you might find useful would be:

id(@foo)/@ID

However, it seems to me that this is not exactly your case. In any case
the list of names can be processed recursively.  

In Saxon there's saxon:tokenize().

Dimitre.


--- Peter Flynn <peter@xxxxxxxxxxx> wrote:
> At Monday, 5 February 2001, you wrote:
> 
> >The ***value*** of the ***single @foo attribute node*** contains
> >multiple entity names.
> >
> >This has nothing to do with the fact that an element has only 0 or 1
> >attribute having a given name.
> 
> So it appears :-) OK, next question: is there a syntax in XPath
> which will give access to each entity name in turn? 
> 
> ///Peter
> 
> 
> 
> 
> 
> 


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