Subject: RE: xsl:for-each?
From: "Michael Kay" <mhkay@xxxxxxxxxxxx>
Date: Sun, 21 Jan 2001 23:24:09 -0000
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> In the template I have:
>
> <xsl:template match="markets">
> <select name="Markets" size="1">
> <xsl:for-each select="markets">
> <option value="@id"/><xsl:value-of select="@name"/>
> </xsl:for-each>
> </select>
> </xsl:template>
>
This template rule is called to process one particular <markets> element.
You xsl:for-each is then asking to process the <markets> elements that are
children of this <markets>, and there aren't any.
> Now, I know this isn't correct. I am confused as to why it
> doesn't work though.
No, your analysis seems to be quite correct...
> is it because the xsl node is
> already selected to "markets" that it is looking inside the
> first market node it comes across and isn't finding anything called
markets?
Yes (in effect - though your terminology is non-standard)
Mike Kay
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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