Subject: Re: Finding the maximun number of nodes
From: Dimitre Novatchev <dnovatchev@xxxxxxxxx>
Date: Fri, 5 Jan 2001 00:27:03 -0800 (PST)
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Actually even simpler:
count(//tr[not(key('numCells', count(td) + 1))]/td)
--- Dimitre Novatchev <dnovatchev@xxxxxxxxx> wrote:
> Use:
>
> <xsl:key name="numCells" match="tr" use="count(td)"/>
>
> <xsl:template name="maxCols">
> <xsl:for-each select="//tr[not(key('numCells', count(td) + 1))]">
>
> <xsl:value-of select="count(td)"/>
> </xsl:for-each>
> </xsl:template>
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