From: "Frank Neugebauer" <neuggs@xxxxxxxxxxx>
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: problem of repetition
Date: Tue, 30 Jan 2001 17:44:18
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Would it be possible to get:
1) Source XML
2) Destination (expected) XML (output)
That would help a lot.
Regards,
Frank.
hello friends,
i have tried the site jenitennison.com.
i am facing one problem.the problem is that in report i am getting same
project name again and again
and the records are also in a repetition. but i have solved the problem of
grouping.means to separate the data of projects and the same project data
in a single table.but this project name is repeating and its records are
also repetiting.
thanks in advance
<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:key name="manish" match="row" use="PROJECT_ID" />
<xsl:output method="html"/>
<xsl:template match="rowset">
<xsl:apply-templates select="row[generate-id(.) = generate-id(key('manish',
PROJECT_ID)[1])]" />
<html>
<head>
<title>Ptss</title>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1"/>
<link rel="stylesheet" href="../../Content_Files/Form.css"/>
</head>
<body>
<xsl:for-each
select="//PROJECT_ID/@value[not(.=following::PROJECT_ID/@value)]" >
<xsl:value-of select="."/>
<xsl:for-each select="//row[PROJECT_ID/@value=current()]">
<xsl:sort select="TASK_NAME/@value"/>
<p><xsl:value-of select="TASK_NAME/@value"/></p>
</xsl:for-each>
</xsl:for-each>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
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