You want the identity transformation:

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
   
	<!-- Match every node whether it is an element or an attribute -->

	<xsl:template match="node()|@*">
			<xsl:copy>
				<xsl:apply-templates select="node()|@*"/>
			</xsl:copy> 
	</xsl:template>
				
	<xsl:template match="/">
				<xsl:apply-templates select="node()|@*"/>
	</xsl:template>
	
</xsl:stylesheet>
>> -----Original Message-----
>> From: Michael Kay [mailto:mhkay@xxxxxxxxxxxx]
>> Sent: Thursday, January 25, 2001 2:58 AM
>> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
>> Subject: RE:  xsl to echo input xml
>> 
>> 
>> > If I want to pass an xml to an xsl, and then have the xsl
>> > simply repeat
>> > what's in the xml, how would I go about that?
>> 
>> <xsl:copy-of select="*"/>
>> 
>> > I thought the following would do it:
>> >
>> > <xsl:template match="*">
>> >    <xsl:apply-templates/>
>> > </xsl:template>
>> >
>> No, this will copy the text nodes to the output but not the 
>> element nodes.
>> I.E, the output will contain no tags.
>> 
>> Mike Kay
>> 
>> 
>>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>> 

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list