Subject: Re: using xsl:copy
From: Frank Hess <hess.frank@xxxxxx>
Date: Tue, 23 Jan 2001 18:19:44 +0100
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Use:
<xsl:template match="/catalog/item">
<xsl:apply-templates select="description"/>
</xsl:template>
<xsl:template match="description">
<xsl:copy-of select="."/>
</xsl:template>
At 11:59 23.01.01 -0500, you wrote:
If I have an xml structure like this:
<catalog>
<item>
<description><b>A nice shoe</b></description>
</item>
</catalog>
and my xsl looks like this:
<xsl:template match="/catalog/item">
<xsl:copy-of select="description"/>
</xsl:template>
my HTML output is:
<description><b>A nice shoe</b></description>
How can I output the html without the <description> tags? I wish to preserve
the <b> tags which may or may not be there.
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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