Subject: getting parents position
From: "Mirick, John" <jmirick@xxxxxxxxxxxx>
Date: Tue, 7 Nov 2000 15:02:07 -0500
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Hey there...
Easy question and Im sure it is somewhere in the FAQ (I just havent been
able to track it down).
Question is in the code..
<xsl:template match="dh:row">
<tr>
<xsl:for-each select="dh:data">
<xsl:call-template name="tableCell">
<xsl:with-param name="cellData"><xsl:value-of
select="."/></xsl:with-param>
</xsl:call-template>
</xsl:for-each>
</tr>
</xsl:template>
<xsl:template name="tableCell">
<xsl:choose>
<!-- ???
every other row should be shaded... this isnt right. Basicly I need the
syntax for getting the value of a parents position()
???-->
<xsl:when test="parent[position() mod 2 = 0]">
<td class="tableshadedRow"><xsl:value-of
select="parent" /><xsl:value-of select="$cellData" /></td>
</xsl:when>
<xsl:otherwise>
<td><xsl:value-of select="$cellData" /></td>
</xsl:otherwise>
</xsl:choose>
Im new at this and pretty baffled right now. Thanks for the help.
John
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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