Suppose we have this XML:

<top>
  <middle id="1">
      <data>value</data>
      <foo>bar</foo>
  </middle>
  <middle id="2">
      <data>value</data>
  </middle>
  <middle id="3">
      <data>value</data>
      <foo>bar</foo>
  </middle>
</top>

I want to match the 'middle' nodes that _don't_ have the 'foo' node (id==2).
This seems to work:

<xsl:template match="/">
  [stuff before]
  <xsl:for-each select="//middle">
    <xsl:if test="not (foo[node()]">
      [Whatever I want to do]
    </xsl:if>
  </xsl:for-each>
</xsl:template>

(You get the general idea.) Isn't there any simpler way to do this??  I'd
rather do something where, in one line, I match the 'middle' nodes without
the 'foo' tag, and then do an unconditional loop over these nodes.

Thanks!

-Ted


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list