Subject: Re: question with using Muenchian/xsl:key (Re: sort/group/count probl em)
From: Goetz Bock <bock@xxxxxxxxxxx>
Date: Sat, 11 Nov 2000 21:33:31 +0100
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On Sat, Nov 11 '00 at 13:47, Xu, Xiaocun wrote:
> [ ...]
> key('items-by-itemid', @itemid) returns all items with the same @itemid in
> the entire XML document. I just want all items with the same @itemid in
> each of the itemlist element, how can I do that?
What about creating the key inside the template that matches itemlist?
<xsl:template match="itemlist">
<xsl:key ...>
</xsl:template>
Not tried, but shoud work,
Goetz.
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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