Subject: Re: how to replace line-feeds with space?
From: Mike Brown <mike@xxxxxxxx>
Date: Tue, 14 Nov 2000 22:41:56 -0700 (MST)
|
Chad Small wrote:
> I found some info on dpawson's basic trouble-shooting under the Replace
> link, but can't seem to make the transformation work.
Actually, you're doing way too much work. If you're replacing a single
character with a single character, all you need is the XPath function
translate().
<xsl:template match="TITLE/text()">
<xsl:value-of select="translate(.,' ',' ')"/>
</xsl:template>
Using tail recursion and substrings is only necessary if you're
doing substring replacement, or replacing characters with elements.
- Mike
____________________________________________________________________
Mike J. Brown, software engineer at My XML/XSL resources:
webb.net in Denver, Colorado, USA http://www.skew.org/xml/
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
|
Cart
