Subject: RE: How To Access a param from style sheet
From: Scott_Boag@xxxxxxxxx
Date: Thu, 19 Oct 2000 13:45:20 -0400
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The best place to ask questions about the Xalan API and behavior is on the
xalan-dev list (mailto:xalan-dev-subscribe@xxxxxxxxxxxxxx, or go to
http://xml.apache.org/mail.html).
-scott
Kay Michael
<Michael.Kay@xxxxxxx> To: "'xsl-list@xxxxxxxxxxxxxxxx'" <xsl-list@xxxxxxxxxxxxxxxx>
Sent by: cc: (bcc: Scott Boag/CAM/Lotus)
owner-xsl-list@mulber Subject: RE: How To Access a param from style sheet
rytech.com
10/19/00 06:28 AM
Please respond to
xsl-list
> I am new to XSLT and also to this list. I have a quick
> question about accessing parameters from XSL style sheets. I am using
Xalan
> XSLT processor in my servlet to transform XML into HTML using XSL. I am
> able to set the stylesheet param using
>
> xslProcessor.setStylesheetParam("sortBy", "receiverId");
>
I'm not a Xalan expert (!) but I seem to recall that the second parameter
is
an XPath expresssion, not a string, so you might need to write
"'receiverId'".
Mike Kay
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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