Did you declare the parameter in the stylesheet?

<xsl:param name="sortBy" />

> -----Original Message-----
> From: Bharat.Chintapally@xxxxxxxxxxxxxxxxx
> [mailto:Bharat.Chintapally@xxxxxxxxxxxxxxxxx]
> Sent: Wednesday, October 18, 2000 4:23 PM
> To: XSL-List@xxxxxxxxxxxxxxxx
> Subject: How To Access a param from style sheet
> 
> 
> Hello:
>      I am new to XSLT and also to this list. I have a quick 
> question about
> accessing parameters from XSL style sheets. I am using Xalan 
> XSLT processor
> in my servlet to transform XML into HTML using XSL.  I am 
> able to set the
> stylesheet param using
> 
>      xslProcessor.setStylesheetParam("sortBy", "receiverId");
> 
> Now I am trying to access this param in the xsl stylesheet to do my
> sorting.. I tried something like the following but I am not
> having much (/any) luck..
> 
> <xsl:sort select="*[name() = $sortBy]"/>
> 
> Any help is really appreciated..
> 
> Thanks
> -- bharat
> 
> ---------------------------------------------------------------
> Bharat Chintapally
> CommerceQuest Inc.
> bharat.chintapally@xxxxxxxxxxxxxxxxx
> New Phone # 813-639-6478
> ---------------------------------------------------------------
> 
> 
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