Your code should work.  What processor are you using?  If you're using IE5,
you need to install the MSXML3 upgrade and install in "replace mode".  Read
this FAQ:

http://www.netcrucible.com/xslt/msxml-faq.htm

Evan Lenz
elenz@xxxxxxxxxxx
http://www.xyzfind.com
XYZFind, the search engine *designed* for XML
Download our free beta software: http://www.xyzfind.com/beta


-----Original Message-----
From: owner-xsl-list@xxxxxxxxxxxxxxxx
[mailto:owner-xsl-list@xxxxxxxxxxxxxxxx]On Behalf Of Dwight Kelly
Sent: Wednesday, October 04, 2000 4:34 PM
To: xsl-list@xxxxxxxxxxxxxxxx
Subject: XSL attribute expression



I am fairly new to XSL and am trying to extract the value of the attribute
'url' from the node 'job' and make it a HTML <A HREF=> link. Is this the
correct syntax? Instead of getting
<A HREF="http://www.apago.com/jobs/1">URL</A>
I am getting
<A HREF="{@url}">URL</A>

here is my xml file fragment:

<job job-id="100" url="http://www.apago.com/jobs/1" />

and my xsl fragment:

<xsl:template match="job">
	<DIV>
	Job <xsl:value-of select="@job-id" />
	<A HREF="{@url}">URL</A>
	</DIV>
</xsl:template>

Thanks,
--
Dwight Kelly
Apago, a division of Essential Technical Services, Inc.
315 Allen Street Cumming, GA 30040
voice:(770) 889-2848  fax:(770) 889-2624 Internet:dkelly@xxxxxxxxx
http://www.apago.com


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