Steve
I think you're looking too hard.
>
> simple question yet its got me stumped.
>
> <xsl:for-each select="a">
> <xsl:for each select = "//b[@aref = current()/@ref]">
> <xsl:value-of select = "//c[@aref =
> current()/current()/@ref"/>
> </xsl:for-each>
> </xsl:for-each>
>
you are missing a "]" in the line
<xsl:value-of select = "//c[@aref = current()/current()/@ref"/>
My recommendation is to go for a beer.
All the best
Mike Ball
Application Services Consultant
Software AG UK
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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