Jeni,

thank you for the hint. It's the XSLT processor.
We have two XSLT processors in use. The first one
is the xalan (this is the one I have the problems).
The output is:

News item 1[2.xml] News item 1[4.xml]

The second one is the xt. I've tried the same
files on the xt and the output is:

News item 1[2.xml] News item 2[4.xml]


Is one of the XSLT processors *the best*? We've
changed from xt to xalan because of the
support. But as it seems it's not the best
choice.

For this problem I have to do a workaround,
because there is no time to change the
XSLT processor. But for the future I
will know.

Thank you very much for your support.

sunny greetings from the lake

Dirk Holstein
--------------------------------------------
web your vision

doubleSlash Net-Business GmbH
Muellerstr. 12/1
88045 Friedrichshafen

Fon 07541 60 47-102
Fax 07541 60 47-111

www.doubleslash.de
dirk.holstein@xxxxxxxxxxxxxx




> Dirk,
>
> >If I do anything like this:
> >
> ><xsl:template match="/">
> >   <xsl:apply-templates
> select="document(/page/folder)/news[@show = 'true']"
> >/>
> ></xsl:template>
> >
> ><xsl:template match="news">
> >   <xsl:variable name="index" select="position()" />
> >   News item <xsl:value-of select="$index" />
> >   ...
> ></xsl:template>
> >
> >I will allways get '1'. Because the 'news' tag is allways the number one
> >position in the current xml file.
>
> I'm very surprised that this is always generating '1'.  What XSLT
> processor
> are you using?  When you use the position() function, it should
> look at the
> position of the current node in the *current node list*, not in the
> 'current XML file'.
>
> Within the template, the current node is the node that's been matched - in
> this case the 'news' element.  The current node list is set by the
> xsl:apply-templates that was used to apply the template.  In this
> case, the
> current node list consists of the nodes specified by the XPath:
>
>   document(/page/folder)/news[@show = 'true']
>
> In your example, this list has two nodes in it: the 'news' element from
> 2.xml and the 'news' element from 4.xml.  So the position() of the first
> should be 1 and the position() of the second should be 2.
>
> I have tested the following files in SAXON and it gives the result that I
> think you are after.  Please let me know what the resulting output should
> look like if I've misinterpreted you.
>
> ---- test.xml ----
> <?xml version="1.0"?>
> <?xml-stylesheet type="text/xsl" href="test.xsl" ?>
> <page>
>   <folder>1.xml</folder>
>   <folder>2.xml</folder>
>   <folder>3.xml</folder>
>   <folder>4.xml</folder>
> </page>
> ----
> ---- 1.xml ----
> <news show="false">
>   1.xml
> </news>
> ----
> ---- 2.xml ----
> <news show="true">
>   2.xml
> </news>
> ----
> ---- 3.xml ----
> <news show="false">
>   3.xml
> </news>
> ----
> ---- 4.xml ----
> <news show="true">
>   4.xml
> </news>
> ----
> ---- test.xsl ----
> <?xml version="1.0"?>
> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
>                 version="1.0">
>
> <xsl:template match="/">
>    <xsl:apply-templates
> select="document(/page/folder)/news[@show='true']" />
> </xsl:template>
>
> <xsl:template match="news">
>   News item <xsl:value-of select="position()" />[<xsl:value-of
>   select="normalize-space(.)" />]
> </xsl:template>
>
> </xsl:stylesheet>
> ----
>
> Command line:  saxon -a -t -o out.xml test.xml
>
> ---- out.xml ----
> <?xml version="1.0" encoding="utf-8" ?>
>   News item 1 [2.xml]
>
>   News item 2 [4.xml]
> ----
>
> I hope this helps,
>
> Jeni
>
> Dr Jeni Tennison
> Epistemics Ltd * Strelley Hall * Nottingham * NG8 6PE
> tel: 0115 906 1301 * fax: 0115 906 1304 * email:
> jeni.tennison@xxxxxxxxxxxxxxxx
>
>


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list