Subject: RE: counting and displaying with xsl?
From: Kay Michael <Michael.Kay@xxxxxxx>
Date: Thu, 8 Jun 2000 11:22:43 +0100
|
> The following has worked for me before:
>
> <xsl:if expr="(childNumber(this) % 5) == 1">
>
Presumably in MS 1998 XSL: neither "expr=" nor "childNumber()" nor "this"
nor "%" nor "==" are valid in XSLT.
In XSLT the equivalent is
<xsl:if test="position() mod 5 = 1">
A wonderful example of how dissimilar these two languages are: five
differences in one line!
Mike Kay
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
|
Cart
