Subject: Re: xsl and url parameter strings
From: David Carlisle <davidc@xxxxxxxxx>
Date: Tue, 15 Feb 2000 01:22:30 GMT
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> What I am trying to get as a result is something like
> <a href="/webcv/system/usermanager/?a=0&u=1"></a>
no, you're not! as xsl can only produce well formed xml and that is not
well formed.
You want to produce <a href="/webcv/system/usermanager/?a=0&u=1"></a>
which is the right way to express that url in xml syntax (and html
syntax, for that matter)
> The error lotusxsl is giving with & is - The reference to entity "u"
> must end with the ';' delimiter.
well, it shouldn't.
It looks like it is reparsing the string in which case it probably wants
&amp;u
but if so its a bug in lotusxsl unless I am mistaken (which is not
enitrely impossible this time of night)
David
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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