As an extension of the position() of parent question from digest 480,
I have a challenge.  How can a template be created, such that it will
print out the complete path of current node from the root?  As an
example:

<A>
  <B>
    <C/>
  </B>
  <B>
    <C/>
    <C/> <--- calling a template with current() here...
  </B>
  <B>
  </B>
</A>

will yield

A:1.B:2.C:2

1  Element 'A' ():
1.1  Text (A): {
  }
1.2  Element 'B' (A):
1.2.1  Text (A,B): {
    }
1.2.2  Element 'C' (A,B): (no child nodes or attributes)
1.2.3  Text (A,B): {
  }
1.3  Text (A): {
  }
1.4  Element 'B' (A):
1.4.1  Text (A,B): {
    }
1.4.2  Element 'C' (A,B): (no child nodes or attributes)
1.4.3  Text (A,B): {
    }
1.4.4  Element 'C' (A,B): (no child nodes or attributes)
1.4.5  Text (A,B): { }
1.4.6  Comment (A,B): {- calling a template with current() here...}
1.4.7  Text (A,B): {
  }
1.5  Text (A): {
  }
1.6  Element 'B' (A):
1.6.1  Text (A,B): {
  }
1.7  Text (A): {
}

--
G. Ken Holman                    mailto:gkholman@xxxxxxxxxxxxxxxxxxxx
Crane Softwrights Ltd.             http://www.CraneSoftwrights.com/s/
Box 266, Kars, Ontario CANADA K0A-2E0   +1(613)489-0999   (Fax:-0995)
Web site: XSL/XML/DSSSL/SGML services, training, libraries, products.
Practical Transformation Using XSLT and XPath      ISBN 1-894049-03-9
Next instructor-led training:  2000-02-27/28,2000-05-11/12,2000-05-15