Subject: Re: position() question
From: David Carlisle <davidc@xxxxxxxxx>
Date: Wed, 17 Nov 1999 12:12:25 GMT
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> Why do I get in version a even numbers 2, 4, 6, ... ?
Modify your template like so:
<xsl:template match="item">
<xsl:variable name="x" select="position()"/>
<xsl:value-of select="
concat('(',preceding-sibling::node()[position() = $x -1],')')"/>
<xsl:call-template name="output-position"/>
</xsl:template>
and you will see what is contained in the nodes at odd positions.
The current node list in the xsl:for-all case is different and only
contains the item nodes (as that is what you selected) so in that case
the items are in positions 1, 2, 3.
David
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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