Hi,

   I have a simple xsl code which  uses the normalize() function.
   
   <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
                   version="1.0"
                   xmlns:xt="http://www.jclark.com/xt"
                   extension-element-prefixes="xt"> 
                   
    <xsl:template match="study">
        <xsl:if test = "condition[normalize(.)]">
             <xsl:value-of select="."/>
        </xsl:if>
    </xsl:template>
                
   
   </xsl:stylesheet>
                
                
   
   I get the following error message using xt:
   
   no such function: normalize
   
   Does xt support the normalize() function? 
   Thanks all.
   
   Minita
   


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