Subject: xsl: how to select slice of tree regarding the node position
From: pietro abate <pietro.abate@xxxxxx>
Date: Wed, 06 Oct 1999 10:16:39 +0200
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Hi,
I've a tree like
|---B
|---B |---D
|---C-|---D
A|---B (1)
|---C-|---D
and I would like to trasform in a tree like
|---B
|---H-|---B
|
|---H-|---newC
|
| |---D
A|---H-|---D
| |---newC
|
|---H-|---B
|
|---H-|---newC
|
|---H-|---D
|---newC
In other words I want ot group the B, and split the C, but in accord
with the position in the original tree;
So I don't know how to select, for example, the B(1) because it's a B
and because it's between two C.If I try to make a template to select
all the B I lose the information about the position, an if I try to
select all the C I lose the possibility of group _all_ the previous B.
I succeded with a little recursive perl (XML::DOM) program, but I would
like to do this in xsl.
Suggestion ?
pietro
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