Subject: RE: How can I get real path ?
From: Jonathan Marsh <jmarsh@xxxxxxxxxxxxx>
Date: Tue, 30 Jun 1998 13:47:38 -0700
|
I was referring an obvious omission in the MSXSL Technology Preview Release,
not an architectural limitation.
-----Original Message-----
From: Oisin McGuinness [mailto:oisin@xxxxxxxx]
Sent: Tuesday, June 30, 1998 10:36 AM
To: xsl-list@xxxxxxxxxxxxxxxx
Cc: oisin@xxxxxxxx
Subject: Re: How can I get real path ?
Concerning the messages of Marsh and Barre, surely all one
needs to do is
process the given XML document with an architecturally aware
process, where <name>, and
<status> inherit from the same element in the architectural
DTD, and have XSL report the child number
in the transformed document. Or will one not be allowed to
transform documents before
styling them?
Oisin McGuinness
Jonathan Marsh said....<jmarsh@xxxxxxxxxxxxx>
>>You can't. There is no way to ask for the number of a
child relative to
>>elements of ANY type. Big hole, huh?
-----Original Message-----
From: Benoît BARRE
[mailto:benoit.barre@xxxxxxxxxx]
Sent: Monday, June 29, 1998 3:22 AM
To: xsl-list@xxxxxxxxxxxxxxxx
Subject: How can I get real path ?
Imagine I have the following XML instance :
<?xml version="1.0"?>
<description>
<document>
<name>a name</name>
<status>a status</status>
<name>a name</name>
</document>
</description>
I want to get something like :
1 description
1.1 document
1.1.1 name
1.1.2 status
1.1.3 name
'path(this)' can't give me what I want.
path gives me :
1 description
1.1 document
1.1.1 name
1.1.1 status // <= that's not what I want
I can't figure out how to do that. Is there
any other
solution ?
Note : I use MSXSL.Exe.
benoit.barre@xxxxxxxxxx
(End included message)
XSL-List info and archive:
http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
|