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Hello,
I thought that the following XPath steps are equivanent:
something[name()='lalala']
something[self::lalala]
However, it isn't so.
----- [test.xml]
<list type="bulleted" x="y">data</list>
----- [/test.xml]
----- [test.xsl]
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="list">
<list1>
<xsl:copy-of select="@*[name()='type']"/>
<list2>
<xsl:copy-of select="@*[self::type]"/>
<xsl:copy-of select="node()"/>
</list2>
</list1>
</xsl:template>
</xsl:stylesheet>
----- [/test.xsl]
----- [result]
<list1 type="bulleted"><list2>data</list2></list1>
----- [/result]
I expected that "list2" will also have the attribute "type", but it
doesn't. Why does it so?
--
Oleg Parashchenko olpa@ http://xmlhack.ru/ XML news in Russian
http://uucode.com/blog/ Generative Programming, XML, TeX, Scheme
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