• From: Rick Jelliffe <rjelliffe@a...>
• To: xml-dev@l...
• Date: Tue, 09 Jan 2007 18:26:32 +1100

Long JingJun wrote:
> Hi all,
>
> My original target is to get the XPath to identify the location of an element in the XML output (as location attribute for an example). So that I can find the original place in the source file when I go through the generated XML output. What I mean full XPath is like this: /document/chapter[2]/section[3]/subject[1]/para[2]
>
> Thanks all. You answered my question.
>  
Heres the code we use in Schematron (I think from David Carlisle 
originally?)

          <xsl:template match="*|@*" mode="get-full-path">

            <xsl:apply-templates select="parent::*" mode="get-full-path"/>
            <xsl:text>/</xsl:text>
            <xsl:if test="count(. | ../@*) = count(../@*)">@</xsl:if>
            <xsl:value-of select="name()"/>
            <xsl:text>[</xsl:text>
              <xsl:value-of 
select="1+count(preceding-sibling::*[name()=name(current())])"/>
              <xsl:text>]</xsl:text>
               </xsl:template>


(XSLT question are better dealt with on the mulberry XSLT list.)

Cheers
Rick Jelliffe

• References:
  • Re: How to get XPath in a XSLT shylesheet
    • From: Long JingJun <longjingjun@y...>