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Maybe you need to replace the or operator you are using('|') by "or".
Good luck
On
Wed, 29 Nov 2006 11:17:59 -0800 "Spencer Tickner"
<spencertickner@g...> wrote:
> Hi List,
>
> Thanks in advance for the help. I think I left my brain in Cuba, and
> cannot seem to figure out this fairly straight forward problem (well
> that and secretly hoping someone has a more elegant way of doing
> this).
>
> So I have a generated XML
>
> <root>
> <view>
> <id>foo</id>
> <name>foo</name>
> </view>
> <view>
> <id>bar_archive</id>
> <name>Bar Archive</name>
> </view>
> <view>
> <id>bar</id>
> <name>bar</name>
> </view>
> <view>
> <id>foo_archive</id>
> <name>Foo Archive</name>
> </view>
> </root>
>
> Issue comes from the fact that every time I get this XML file, the
> <view>s are in different, random order. I need them in a specific
> order every time. Along with this, sometimes a <view> exists, and
> sometimes it doesn't which should be reflected in the output. So far
> my XSL looks something like this (I've marked where my if statement is
> failing):
>
> <?xml version='1.0'?>
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
>
> <xsl:template match="/">
>
> <html>
> <body>
> <!-- This if statement fails (Value of expression cannot be converted
> to a node-set in expression) -->
> <xsl:if test="root//view/id = 'foo' | root//view/id = 'bar'">
> <p>Here are the foo bars</p>
> <ul>
> <xsl:apply-templates select="root//view[id='bar']"/>
> <xsl:apply-templates select="root//view[id='foo']"/>
> </ul>
> </xsl:if>
>
> <xsl:if test="contains(root//view/id, 'archive')">
> <p>Here are archive foo bars</p>
> <blockquote>
> <xsl:apply-templates select="root//view[id = 'bar_archive']"/>
> <xsl:apply-templates select="root//view[id = 'foo_archive']"/>
> </blockquote>
> </xsl:if>
>
> </body>
> </html>
>
> </xsl:template>
>
> <xsl:template match="view" priority="5">
> <li><xsl:value-of select="name"/></li>
> </xsl:template>
>
> <xsl:template match="view[contains(id, 'archive')]" priority="10">
> <p><xsl:value-of select="name"/></p>
> </xsl:template>
>
> </xsl:stylesheet>
>
> Any thoughts would be greatly appreciated. (PS - I am stuck with 1.0)
>
> Thanks you,
>
> Spencer Tickner
>
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