• To: "'Bill Riegel'" <BRiegel@l...>,<xml-dev@l...>
• Subject: RE: is there a way to break out of the xsl:for-each loop ?
• From: "Michael Kay" <michael.h.kay@n...>
• Date: Tue, 23 Mar 2004 16:01:27 -0000
• In-reply-to: <830BF4914C3C4B4EB1C438D93ABF897A044423@l...>
• Thread-index: AcQQ5GZp1VbF+4LPRciHab4/IHnArAAC31Fw

You seem to be assuming that the elements are processed serially, starting
with the first. Such an assumption is invalid.

Write

<xsl:for-each select="$list-of-nodes[string(.)=$mySearchItem][1]">

Michael Kay 

# -----Original Message-----
# From: Bill Riegel [mailto:BRiegel@l...] 
# Sent: 23 March 2004 14:38
# To: 'xml-dev@l...'
# Subject:  is there a way to break out of the 
# xsl:for-each loop ? 
# 
# 
# What to look thru a listOfNodes, and set contents on a 
# variable, foundIt, when I found what I am looking for, then break. 
# 
# <xsl:variable name="foundIt">
# 	<xsl:for-each select="$listofNodes">
# 		<xsl:if test="string(current()) = $mySearchItem">
# 			<!-- break out of look if found what I 
# am looking for -->
# 			<xsl:break>  
# 		</xsl:if>
# 	</xsl:for-each>
# </xsl:variable>
# 
# <!-- do something with foundIt -->
# 
# Bill Riegel
# LandMark Graphics
# 713-839-3388
# 
# 
# 
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• References:
  • is there a way to break out of the xsl:for-each loop ?
    • From: Bill Riegel <BRiegel@l...>

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