• To: "Henry S. Thompson" <ht@c...>,<xml-dev@l...>
• Subject: Re: Extending Types in xml schema
• From: "Jeff Greif" <jgreif@a...>
• Date: Fri, 31 Oct 2003 10:09:31 -0800
• References: <6B6D183502EF3D45992B52C14A614133013DAB6D@a...> <f5bu15pnxse.fsf@e...>

I think the OP was trying to extend a type comprising a repeating choice by
adding another branch to that choice.  The base type was (a|b|c)* and he
wanted the derived type to be (a|b|c|d)*.

I'm only interpreting for him because I'm curious about the answer to that
question.

Jeff

----- Original Message ----- 
From: "Henry S. Thompson" <ht@c...>
To: "Craig Edmunds" <craig.edmunds@c...>
Cc: <xml-dev@l...>
Sent: Friday, October 31, 2003 9:04 AM
Subject: Re:  Extending Types in xml schema


> Not entirely clear what your required functionality is.
>
> You could get flexible functionality, without multiple types being
> involved, as follows:
>
> Schema 1:
>         <xs:element name="slug" abstract="true"/>
> <xs:element name="br" substitutionGroup="slug"/>
> <xs:element name="p" type="textBaseType" substitutionGroup="slug"/>
> <xs:element name="span" type="spanType" substitutionGroup="slug"/>
> <xs:element name="ul" type="ulType" substitutionGroup="slug"/>
> <xs:element name="table" type="tableType" substitutionGroup="slug"/>
> <xs:complexType name="textBaseType" mixed="true">
>   <xs:element ref="slug" minOccurs="0" maxOccurs="unbounded"/>
>         </xs:complexType>
>
>
> Schema 2:
>
>         <xs:include schemaLocation="schema 1"/>
> <xs:element name="li" type="tableType" substitutionGroup="slug"/>

• References:
  • Extending Types in xml schema
    • From: "Craig Edmunds" <craig.edmunds@c...>
  • Re: Extending Types in xml schema
    • From: ht@c... (Henry S. Thompson)

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